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**A Short Glimpse Into Sandown Town In New Hampshire**

Sandown is one among the towns in the Rockingham province of New Hampshire State in the United States.

**Geography: **

Sandown covers an area of about 14.4 square miles, of that 0.5 square miles is covered by the water body and 13.9 square miles is covered by the land. This town is drained by the River called Exeter; Phillips pond towards the south of heart of the town drains north part to the Exeter. Showell pond is a very smaller water body that drains northwest to Phillips town. Angle Pond in the southern east part of the Sandown as well as Cub Pond along this town eastern border drains east to the Powwow River. The greatest point in this town is the top of Hoyt Hill that is at the height of about 505 feet above the sea level, adjacent to the Sandown Southwest corner.

**Education system offered in Sandown **

When it comes to the matter of schools available for the students of this town, Sandown caters plenty of schools namely

Sandown Central School, offers education for Pre-K grades and it is located within Sandown campus. The Sandown North Elementary School, offers education from grades 1st to 5th and it is located within Sandown campus. A Timberlane Regional Middle School, offers education from grades 6th to 8th and it is located in Plaistow. And, a Timberlane Regional High School, offers education from grades 9th to 12th and it is located in Plaistow.

**Police department in Sandown **

The department of police is trying to improve the quality of the resident’s life via their outstanding service to public, impartial prosecution of the law and protection of property as well as persons. The aim will be adept via the following values: -

1. They will offer expert concerned responses to several social and medical emergency conditions.

2. They will optimize the communication with residents to accordingly identify requirements as well as apprehend criminals.

3. They will cleverly deploy resources handy to decrease the level of the criminal victimization.

4. They will treat all individuals with courtesy and respect

**Recreation**

The Recreation Commission is an elected volunteer Commission that supervises the Parks and Recreation Department and is devoted to scheming recreational activities for citizens of Sandown incorporating senior citizens, adults and children; relating with other departments of the Sandown in expedite recreational requirements of citizens; controlling recreational sites in this town incorporating the Seeley Park and Beach, the Edward C. Garvey Recreation Facility and Roy L. Miller Recreational Facility.

Substituting
the known values in the second part of Equation 29, we find that the stress in
the steel s equals about 15,500 pounds per square inch. Assume that a concrete
floor is loaded so that the total weight of live and dead load is 200 pounds
per square foot; assume that the T-concrete concrete beams are to be 5 feet apart,
and that the concrete slab is to be 4 inches thick; assume that the span of the
concrete beams is 30 feet. We therefore have an area of 150 square feet to be
supported by each concrete beam, which will give a total load of 30,000 pounds
on each concrete beam. The moment at the center of such a concrete beam will
therefore be equal to the total load, multiplied by one-eighth of the span
(expressed, in inches), and the moment is therefore 1,350,000 inch-pounds. As a
trial value, we shall assume that the concrete beam is to be reinforced with
six i-inch bars, which have an area of 3.37 square
inches. Substituting this value of the area in the second part of Equation 35,
and assuming that s = 16,000 pounds per square inch, we find as an approximate
value for d - x, that it will equal 25 inches.

This is very much greater than
the value of d that would be found from substituting the proper values in
Equation 36, so that we know at once that the problem must be solved by the
methods of Case 1. For a 4-inch concrete slab, the value of x must be somewhere
between 1.33 and 2.0. As a trial value, we may call it 1.5, and this means that
d will equal 26.5. Assuming that this concrete slab is to be made of concrete
using a value for r = 12, we know all the values in Equation 34, and may solve
for lcd, which we find to equal 5.54 inches. As a
check on the approximations made above, we may- substitute this value of lcd, and also the value of t in Equation 33, and obtain a
more precise value of x, which we find to equal 1.62. Substituting the value of
the moment and the other known quantities in the upper formula of Equation 35,
we may solve for the value of c, and obtain the value that c = 352 pounds per
square inch. This value for c is so very moderate that it would probably be
economy to assume a lower value for the area of the steel, and increase the
unit-compression in the concrete; but this solution will not be here worked
out.

A great deal of T-concrete beam computation is done on the basis that the
center of pressure of the concrete is at the middle of the concrete slab, and
therefore that the lever-arm of the steel ci - - t.
From these assumptions we may write the approximate formula: M>As (d—t) If
the values of M, and s are known or assumed, we may assume a reasonable value
for either A or (ci - I) and calculate the corresponding
value of the other. On the assumption that the concrete slab takes all the
compression, the distance between the steel and the center of compression of
the concrete varies between (ci - t) and (d < c) which
is the approximate value when the concrete beam becomes so small that it merges
into the concrete slab. The smaller value (ci - t) is
the absolute limit which is never reached. Therefore the lever-arm is always
larger than (ci - t). Therefore, if we use Equation
37 to compute the area of steel A for a definite moment LVI, and unit steel
tension s, the resulting value of A for an assumed depth ci,
or the resulting value of ci for an assumed area A,
will be larger than necessary. In either case the result is safe, but
uneconomically so. As an illustration, using the values in Example 2, Article
291, of M, = 1,350,000; s = 16,000; (d - t) = (26.5 - 2) = 24.5, the resulting
value of A = 3 44 square inches, which is larger than the more precise value
previously computed. Equation 37 is particularly applicable when the neutral
axis is in the rib.**
**

**Are You in Sandown ****New Hampshire****? Do You
Need Concrete Cutting?
**

**We Are Your Local
Concrete Cutter
**

**Call 603-622-4441
**

**We Service Sandown NH
and all surrounding Cities & Towns
**